|
|
Rank: Member
Groups: Registered Users
Joined: 3/25/2011 Posts: 13
|
I'm currently having diffuculty with the distributive property. Here's how I did one problem.
8x + 3(7x - 6)
8x times 7x 8x times 6 + 3
56x + 48
Is this right or wrong ?
Also is there a good website where I can practice doing the distributive property ? I know that the formula is a (b+c) = ab + ac
But everytime I try this with the problems on this page
http://worksheetplace.com/index.php?function=DisplayCategory&showCategory=Y&links=3&id=104&link1=40&link2=103&link3=104
I keep getting it wrong. Is it something I'm doing ?
I'll post some examples when I get a reply.
|
|
|
Rank: Advanced Member
Groups: Registered Users
Joined: 3/16/2011 Posts: 44
|
well u r right, the distributive property says tht a(b+c) = ab + ac and according to this property when we solve your qstion which is 8x + 3(7x - 6)...first we apply the distributive property on 3(7x - 6) and we will get 21x - 18 and now there is 8x in addition and we will add the like terms which will give us the final answer as 29x - 18...y were u multiplying the terms with 8x??.. it was in addition so u have to add it to the result you got after applying the distributive property..
|
|
|
Rank: Member
Groups: Registered Users
Joined: 3/25/2011 Posts: 13
|
I'm having problems with the worksheets on this site.
http://worksheetplace.com/index.php?function=DisplayCategory&showCategory=Y&links=3&id=104&link1=40&link2=103&link3=104
Especially the upper level ones. Could you show me how to do these three
A. n(3n+ 6) + 6n
B. 8x(4 + 3x) + 10x
C. −3x+4x(8 − 10x)
|
|
|
Rank: Advanced Member
Groups: Registered Users
Joined: 3/16/2011 Posts: 44
|
A. n(3n+ 6) + 6n
first use the distributive property to open the brackets..distribute n over 3n + 6 and you will get 3n^2 + 6n now another 6n is in the addition of the whole result we got after applying the distributive property so we will add 6n to get the final answer as 3n^2 + 12n.
B. 8x(4 + 3x) + 10x
simlarly u can solve this problem too. distribute 8x over 4 + 3x and then add 10x to the answer you get. the final answer would be 42x + 24x^2.
C. −3x+4x(8 − 10x)
similarly here we first distribute 4x over 8 - 10x to get 32x - 40x^2 and then subtract 3x from the result we got to get the final answer as 29x - 40x^2,
i hope i am clear. you can ask me in case of any doubts.
|
|
|
Rank: Member
Groups: Registered Users
Joined: 3/25/2011 Posts: 13
|
mohit wrote:
A. n(3n+ 6) + 6n
first use the distributive property to open the brackets..distribute n over 3n + 6 and you will get 3n^2 + 6n now another 6n is in the addition of the whole result we got after applying the distributive property so we will add 6n to get the final answer as 3n^2 + 12n.
B. 8x(4 + 3x) + 10x
simlarly u can solve this problem too. distribute 8x over 4 + 3x and then add 10x to the answer you get. the final answer would be 42x + 24x^2.
C. −3x+4x(8 − 10x)
similarly here we first distribute 4x over 8 - 10x to get 32x - 40x^2 and then subtract 3x from the result we got to get the final answer as 29x - 40x^2,
i hope i am clear. you can ask me in case of any doubts.
Did you use the exponential rules, cause in another book I'm reading the author explains the five exponential rules before he explains the distributive property. Also in all the examples do you have to use the exponential rules ?
Thanks.
|
|
|
Rank: Advanced Member
Groups: Registered Users
Joined: 3/16/2011 Posts: 44
|
well exponential rules are the basis of every multiplication and division so u always have to keep them in mind while solving any mathematical question for example when v take ur question "n(3n+ 6) + 6n". in this case while applying the distributive property we multiplied n with 3n in this case 3 is a constant term so we take it outside and multiple n with n now the first rule of exponential says tht if in multiplication the bases are same then the powers adds up so when u multiply n with n base(n) is same so we add the powers(1+1=2) and we will get the answer n^2..
|
|
|
|
Guest
|
YAFPro Theme Created by Jaben Cargman (Tiny Gecko)Powered by YAF 1.9.3 RC2 |
YAF © 2003-2008, Yet Another Forum.NETThis page was generated in 0.094 seconds.