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dardar72
#1 Posted : Sunday, June 24, 2012 10:02:13 PM
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consider the funcations f(x)=x^3-3 and g(x)=3/x+3  what is f(g(x))?


lisa
#2 Posted : Tuesday, June 26, 2012 2:26:56 PM
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[dardar72 wrote:]

consider the funcations f(x)=x^3-3 and g(x)=3/x+3  what is f(g(x))?


 

Hi!

 

I guess that your functions are the following

\\f(x)=x^{3}-3\\\\g(x)=\frac{3}{x}+3\\

The function

f(g(x)) tells us that we want to replace all the x:es with the expression for g(x)

f(g(x))=\left ( \frac{3}{x}+3 \right )^{3}-3\\

From here you just have to simplify the expression to its simplest form

\\f(g(x))=\left ( \frac{3}{x}+3 \right )^{3}-3\\\\\\=\left ( \frac{3}{x}+3 \right )\left ( \frac{3}{x}+3 \right )^{2}-3\\\\\\=\left ( \frac{3}{x}+3 \right )\left ( \frac{9}{x^{2}}+\frac{18}{x}+9 \right )-3\\\\\\=\frac{27}{x^{3}}+\frac{27}{x^{2}}+\frac{54}{x^{2}}+\frac{54}{x}+\frac{27}{x}+27-3\\\\\\=\frac{27}{x^{3}}+\frac{81}{x^{2}}+\frac{81}{x}+24\\

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