Math forum

 Russian roulette Options
johan
 #1 Posted : Monday, April 04, 2011 1:24:46 PM

Joined: 1/26/2011
Posts: 22

Assuming both players take turns what is the probability the player who goes first will lose at Russian roulette using a gun with six chambers?

Slinger17
 #2 Posted : Wednesday, April 06, 2011 11:16:30 AM
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Joined: 3/23/2011
Posts: 5

50%. The first person loses if the bullet is in chambers 1,3, or 5. 3/6 = 50%

bobbym
 #3 Posted : Thursday, April 07, 2011 2:29:25 AM
Rank: Newbie

Groups: Registered Users

Joined: 3/9/2011
Posts: 1

Hi;

If you tree this process you will see that going first is a severe disadvantage.

Summing the series to infinity.

So the probability of the first player being killed is 6 / 11. Make sure you go second.

This assumes that the game is they spin the chamber before each shot.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

Success is the ability to go from one failure to another with no loss of enthusiasm.
Slinger17
 #4 Posted : Thursday, April 07, 2011 10:04:17 AM
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Joined: 3/23/2011
Posts: 5

I was assuming that they spun once and took turns from there. It's been a while since I've played Russian Roulette

mohit
 #5 Posted : Thursday, April 07, 2011 8:30:54 PM

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Joined: 3/16/2011
Posts: 44

i think 6/11 is the correct answer...

mohit
 #6 Posted : Thursday, April 07, 2011 9:26:19 PM

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Joined: 3/16/2011
Posts: 44

lemme xplain it in my way..m assuming tht there is only one bullet in the chamber and u spin the chamber after everytym u pull the trigger...let the probability of person losing the game be p which can be done only in one way nw if he doesnt lose then the probability will be 1-p caz nw the second person has probability "p" of losing the game nd this can b done when the first person shots an empty bullet means in 5 ways so total probability will be p = 1/6 + 5(1-p)/6...solving it for p will give u the answer to be p = 6/11...

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