Find x value

Name: Find x value
Uploaded: 2011-02-08
Description: Solution Multiply the left side by $\frac{x+1}{x+1}$ and the right side by $\frac{7}{7}$$$\frac{x+1}{x+1} \cdot \frac{1}{7}=\frac{4}{x+1}\cdot\frac{7}{7}$$$$\frac{x+1}{7(x+1)}=\frac{4\cdot7}{7(x+1)}$$The denominators can now cancel each other$$x+1=28$$Subtract 1 from both sides$$x+1-1=28-1$$$$x=27$$The answer: B

1. If $\frac{1}{7}=\frac{4}{x+1}$, what is the value of $x$?

Multiply the left side by $\frac{x+1}{x+1}$ and the right side by $\frac{7}{7}$

$$\frac{x+1}{x+1} \cdot \frac{1}{7}=\frac{4}{x+1}\cdot\frac{7}{7}$$

$$\frac{x+1}{7(x+1)}=\frac{4\cdot7}{7(x+1)}$$

The denominators can now cancel each other

$$x+1=28$$

Subtract 1 from both sides

$$x+1-1=28-1$$

$$x=27$$

The answer: B